.5x^2=x-.5

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Solution for .5x^2=x-.5 equation:


Simplifying
0.5x2 = x + -0.5

Reorder the terms:
0.5x2 = -0.5 + x

Solving
0.5x2 = -0.5 + x

Solving for variable 'x'.

Reorder the terms:
0.5 + -1x + 0.5x2 = -0.5 + x + 0.5 + -1x

Reorder the terms:
0.5 + -1x + 0.5x2 = -0.5 + 0.5 + x + -1x

Combine like terms: -0.5 + 0.5 = 0.0
0.5 + -1x + 0.5x2 = 0.0 + x + -1x
0.5 + -1x + 0.5x2 = x + -1x

Combine like terms: x + -1x = 0
0.5 + -1x + 0.5x2 = 0

Begin completing the square.  Divide all terms by
0.5 the coefficient of the squared term: 

Divide each side by '0.5'.
1 + -2x + x2 = 0

Move the constant term to the right:

Add '-1' to each side of the equation.
1 + -2x + -1 + x2 = 0 + -1

Reorder the terms:
1 + -1 + -2x + x2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -2x + x2 = 0 + -1
-2x + x2 = 0 + -1

Combine like terms: 0 + -1 = -1
-2x + x2 = -1

The x term is -2x.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2x + 1 + x2 = -1 + 1

Reorder the terms:
1 + -2x + x2 = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -2x + x2 = 0

Factor a perfect square on the left side:
(x + -1)(x + -1) = 0

Calculate the square root of the right side: 0

Break this problem into two subproblems by setting 
(x + -1) equal to 0 and 0.

Subproblem 1

x + -1 = 0 Simplifying x + -1 = 0 Reorder the terms: -1 + x = 0 Solving -1 + x = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + x = 0 + 1 x = 0 + 1 Combine like terms: 0 + 1 = 1 x = 1 Simplifying x = 1

Subproblem 2

x + -1 = 0 Simplifying x + -1 = 0 Reorder the terms: -1 + x = 0 Solving -1 + x = 0 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + x = 0 + 1 x = 0 + 1 Combine like terms: 0 + 1 = 1 x = 1 Simplifying x = 1

Solution

The solution to the problem is based on the solutions from the subproblems. x = {1, 1}

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